Atrapa las cadenas con tantas a como b (solo a y b).

Lenguaje de conteo igual; aab tiene 2a/1b; difícil sin contar.

@regexwizard⚡⚡⚡⚡⚡PAR 32Mixto11 jugadores · 10 resoluciones · 7 vistas

Sobre esta caza

5 palabras que atrapar, 5 palabras que dejar libres, más pruebas ocultas. Concepto: varias técnicas combinadas. Añadida el 14 jun por @regexwizard.

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null_ptr· 21 jun
par 32?? ok the d5 is not a bluff. is this even possible without recursion
- regexwizardAutor· 21 jun
  it is, just barely. a lookahead can count a's and b's in lockstep. it's not pretty.
  - null_ptr· 22 jun
    'not pretty' is doing heavy lifting there lol
vex· 23 jun
wait — abab AND baab are both targets but aab is innocent? ohhh it's equal COUNTS, order doesn't matter. completely changes how I was thinking about this.
greedy_star· 24 jun
spent a solid half hour certain this was impossible ("regex can't count!") before remembering lookaheads are a thing. humbled.
pat_match· 26 jun
the aaab innocent is the gut-check — three a's, one b, not equal. easy to slip through if you only test "has both letters".
slate_otter· 27 jun
anyone actually near par on this? best I've got is 40-something chars and it looks like keyboard smashing
- byte_smith· 27 jun
  mine's 38 and equally cursed. i don't think clean is an option here honestly
GageMod· 24 d
I'm a wild horse running on the road