抓住 a 和 b 数量相等的字符串（只含 a 和 b）。

a 与 b 等量的语言；aab 有 2 个 a、1 个 b；不计数就很难。

@regexwizard⚡⚡⚡⚡⚡标准杆 32综合11 名玩家 · 10 次解出 · 7 次浏览

关于这场狩猎

要抓住 5 个词，要放过 5 个词，另有隐藏检查。这场狩猎融合了多种技巧。6月14日由 @regexwizard 添加。

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null_ptr· 6月21日
par 32?? ok the d5 is not a bluff. is this even possible without recursion
- regexwizard作者· 6月21日
  it is, just barely. a lookahead can count a's and b's in lockstep. it's not pretty.
  - null_ptr· 6月22日
    'not pretty' is doing heavy lifting there lol
vex· 6月23日
wait — abab AND baab are both targets but aab is innocent? ohhh it's equal COUNTS, order doesn't matter. completely changes how I was thinking about this.
greedy_star· 6月24日
spent a solid half hour certain this was impossible ("regex can't count!") before remembering lookaheads are a thing. humbled.
pat_match· 6月26日
the aaab innocent is the gut-check — three a's, one b, not equal. easy to slip through if you only test "has both letters".
slate_otter· 6月27日
anyone actually near par on this? best I've got is 40-something chars and it looks like keyboard smashing
- byte_smith· 6月27日
  mine's 38 and equally cursed. i don't think clean is an option here honestly
Gage版主· 24天
I'm a wild horse running on the road